What is the total capacitance of a circuit containing three capacitors in parallel with capacitances of 0.02 microfarad, 0.05 microfarad, and 0.10 microfarad, respectively?

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Enhance your understanding of the fundamentals of electricity with the AMT General Exam. Study with multiple-choice questions crafted to improve your knowledge and confidence. Prepare effectively for your success!

Multiple Choice

What is the total capacitance of a circuit containing three capacitors in parallel with capacitances of 0.02 microfarad, 0.05 microfarad, and 0.10 microfarad, respectively?

Explanation:
In a parallel arrangement, the total capacitance equals the sum of the individual capacitances because each capacitor shares the same voltage and contributes its stored charge to the total. Add the values: 0.02 μF + 0.05 μF + 0.10 μF = 0.17 μF. That is 0.170 μF, or 170 nF. The other options don’t match this sum, either due to different unit scales or incorrect addition.

In a parallel arrangement, the total capacitance equals the sum of the individual capacitances because each capacitor shares the same voltage and contributes its stored charge to the total. Add the values: 0.02 μF + 0.05 μF + 0.10 μF = 0.17 μF. That is 0.170 μF, or 170 nF. The other options don’t match this sum, either due to different unit scales or incorrect addition.

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