What is the total capacitance of a circuit containing three capacitors with capacitances of 0.25 microfarad, 0.03 microfarad, and 0.12 microfarad, respectively?

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Multiple Choice

What is the total capacitance of a circuit containing three capacitors with capacitances of 0.25 microfarad, 0.03 microfarad, and 0.12 microfarad, respectively?

Explanation:
When capacitors are connected in parallel, their capacitances add together. Add the values: 0.25 μF + 0.03 μF + 0.12 μF = 0.40 μF. So the total is 0.4 μF (which is also 400 nF or 400,000 pF). The option that matches this value is 0.4 μF. The 0.04 μF choice would be too small by a factor of 10.

When capacitors are connected in parallel, their capacitances add together. Add the values: 0.25 μF + 0.03 μF + 0.12 μF = 0.40 μF. So the total is 0.4 μF (which is also 400 nF or 400,000 pF). The option that matches this value is 0.4 μF. The 0.04 μF choice would be too small by a factor of 10.

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