What happens to the current in a voltage step-up transformer with a ratio of 1 to 4?

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Enhance your understanding of the fundamentals of electricity with the AMT General Exam. Study with multiple-choice questions crafted to improve your knowledge and confidence. Prepare effectively for your success!

Multiple Choice

What happens to the current in a voltage step-up transformer with a ratio of 1 to 4?

Explanation:
When a transformer steps up voltage, it must reduce current to keep power roughly the same. In an ideal transformer, the voltage ratio equals the turns ratio (Vs/Vp = Ns/Np), and the currents relate inversely (Is/Ip = Np/Ns). So with a turns ratio of 1 to 4, the secondary voltage becomes four times the primary (Vs = 4 Vp), and the secondary current becomes one quarter of the primary (Is = Ip/4). That’s why the current is stepped down by a 4:1 ratio. In real transformers there are losses, but the basic inverse relationship between voltage increase and current decrease still governs the behavior.

When a transformer steps up voltage, it must reduce current to keep power roughly the same. In an ideal transformer, the voltage ratio equals the turns ratio (Vs/Vp = Ns/Np), and the currents relate inversely (Is/Ip = Np/Ns). So with a turns ratio of 1 to 4, the secondary voltage becomes four times the primary (Vs = 4 Vp), and the secondary current becomes one quarter of the primary (Is = Ip/4). That’s why the current is stepped down by a 4:1 ratio. In real transformers there are losses, but the basic inverse relationship between voltage increase and current decrease still governs the behavior.

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