Two equal capacitors of 100 μF each are connected in series. The total capacitance is

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Enhance your understanding of the fundamentals of electricity with the AMT General Exam. Study with multiple-choice questions crafted to improve your knowledge and confidence. Prepare effectively for your success!

Multiple Choice

Two equal capacitors of 100 μF each are connected in series. The total capacitance is

Explanation:
When capacitors are in series, the total capacitance is smaller than any individual capacitor, and for two equal values it becomes half of one capacitor. The formula is 1/C_eq = 1/C1 + 1/C2. With two 100 μF capacitors: 1/C_eq = 1/100 μF + 1/100 μF = 2/100 μF = 1/50 μF, so C_eq = 50 μF. Therefore the total capacitance is 50 μF. (If they were in parallel, you'd get 200 μF.)

When capacitors are in series, the total capacitance is smaller than any individual capacitor, and for two equal values it becomes half of one capacitor. The formula is 1/C_eq = 1/C1 + 1/C2. With two 100 μF capacitors: 1/C_eq = 1/100 μF + 1/100 μF = 2/100 μF = 1/50 μF, so C_eq = 50 μF. Therefore the total capacitance is 50 μF. (If they were in parallel, you'd get 200 μF.)

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