In a series circuit, the total resistance equals the sum of the individual resistances.

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Multiple Choice

In a series circuit, the total resistance equals the sum of the individual resistances.

Explanation:
When resistors are in series, the same current flows through each one and the voltage across the whole string is the sum of the individual voltages. Each voltage drop is V_i = I · R_i, so the total voltage is V_total = V1 + V2 + … = I · (R1 + R2 + …). The total resistance is V_total divided by the current, giving R_total = (I · (R1 + R2 + …)) / I = R1 + R2 + …. So the total resistance in a series circuit is the sum of the individual resistances. The other expressions don’t apply here: the product isn’t how series resistance adds, the reciprocal of the sum relates to parallel circuits (1/R_total = 1/R1 + 1/R2 + …), and taking a difference isn’t the standard way resistances combine in simple networks.

When resistors are in series, the same current flows through each one and the voltage across the whole string is the sum of the individual voltages. Each voltage drop is V_i = I · R_i, so the total voltage is V_total = V1 + V2 + … = I · (R1 + R2 + …). The total resistance is V_total divided by the current, giving R_total = (I · (R1 + R2 + …)) / I = R1 + R2 + …. So the total resistance in a series circuit is the sum of the individual resistances. The other expressions don’t apply here: the product isn’t how series resistance adds, the reciprocal of the sum relates to parallel circuits (1/R_total = 1/R1 + 1/R2 + …), and taking a difference isn’t the standard way resistances combine in simple networks.

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