In a circuit with 30 V across two series resistors of 10 Ω and 20 Ω, what is the current through the circuit?

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Multiple Choice

In a circuit with 30 V across two series resistors of 10 Ω and 20 Ω, what is the current through the circuit?

Explanation:
In a series circuit, the same current flows through every component, and the resistances add up to give the total resistance. Here, the resistors are in series, so they add to 10 Ω + 20 Ω = 30 Ω. With 30 V across the combination, the current is I = V / R_total = 30 V / 30 Ω = 1 A. So the circuit current is 1 ampere. This matches the idea that the same current flows through both resistors in series.

In a series circuit, the same current flows through every component, and the resistances add up to give the total resistance. Here, the resistors are in series, so they add to 10 Ω + 20 Ω = 30 Ω. With 30 V across the combination, the current is I = V / R_total = 30 V / 30 Ω = 1 A. So the circuit current is 1 ampere. This matches the idea that the same current flows through both resistors in series.

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