If the 0.03 μF capacitor is removed from a parallel network of 0.25 μF, 0.03 μF, and 0.12 μF, what is total capacitance?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Enhance your understanding of the fundamentals of electricity with the AMT General Exam. Study with multiple-choice questions crafted to improve your knowledge and confidence. Prepare effectively for your success!

Multiple Choice

If the 0.03 μF capacitor is removed from a parallel network of 0.25 μF, 0.03 μF, and 0.12 μF, what is total capacitance?

Explanation:
In a parallel capacitor network, the total capacitance is the sum of all individual capacitances. If the 0.03 μF capacitor is removed, you’re left with 0.25 μF and 0.12 μF in parallel, so the total is 0.25 + 0.12 = 0.37 μF. The other numbers don’t fit because they would require including the removed capacitor or miscounting the remaining values (for example, 0.28 μF would come from 0.25 + 0.03, which isn’t the case after removal).

In a parallel capacitor network, the total capacitance is the sum of all individual capacitances. If the 0.03 μF capacitor is removed, you’re left with 0.25 μF and 0.12 μF in parallel, so the total is 0.25 + 0.12 = 0.37 μF. The other numbers don’t fit because they would require including the removed capacitor or miscounting the remaining values (for example, 0.28 μF would come from 0.25 + 0.03, which isn’t the case after removal).

More Multiple Choice Questions
Subscribe

Get the latest from Passetra

You can unsubscribe at any time. Read our privacy policy