A 14-ohm resistor is in a circuit carrying 0.05 ampere. How much power does the resistor dissipate?

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Multiple Choice

A 14-ohm resistor is in a circuit carrying 0.05 ampere. How much power does the resistor dissipate?

Explanation:
Power in a resistor is P = I^2R. With a current of 0.05 A and resistance 14 Ω, P = (0.05)^2 × 14 = 0.0025 × 14 = 0.035 W, which is 35 milliwatts. So the resistor dissipates 35 mW. Since that amount is not less than 35 mW, the statement “at least 35 milliwatts” correctly describes the dissipation. (The exact value is 35 mW, and answers that claim less power would be incorrect.)

Power in a resistor is P = I^2R. With a current of 0.05 A and resistance 14 Ω, P = (0.05)^2 × 14 = 0.0025 × 14 = 0.035 W, which is 35 milliwatts. So the resistor dissipates 35 mW. Since that amount is not less than 35 mW, the statement “at least 35 milliwatts” correctly describes the dissipation. (The exact value is 35 mW, and answers that claim less power would be incorrect.)

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